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-75=12x-5x^2
We move all terms to the left:
-75-(12x-5x^2)=0
We get rid of parentheses
5x^2-12x-75=0
a = 5; b = -12; c = -75;
Δ = b2-4ac
Δ = -122-4·5·(-75)
Δ = 1644
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1644}=\sqrt{4*411}=\sqrt{4}*\sqrt{411}=2\sqrt{411}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{411}}{2*5}=\frac{12-2\sqrt{411}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{411}}{2*5}=\frac{12+2\sqrt{411}}{10} $
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